If f:[a,b]→R is continuous on a closed interval and differentiable on (a,b), then there exists ξ∈[a,b] such that f(b)−f(a)=f′(ξ)(b−a).
More generally, if g:[a,b]→R is similarly continuous on [a,b] and differentiable on (a,b), then there exists a ξ with (f(b)−f(c))g′(ξ)=(g(b)−g(a))f′(ξ). What this means graphically:
If {fn} is a sequence of functions where
- each fn is differentiable,
- there is some G such that ‖∑n≤Nf′n−G‖∞N→∞⟶0, and
- there exists at least one point 1 x0 such that ∑fn(x) converges (pointwise),
then there exists an F such that 2 ‖∑n≤Nfn−F‖∞N→∞⟶0F′=g.
A function f:(a,b)→R is Lipschitz ⟺f is differentiable and f′ is bounded. In this case, |f′(x)|≤C, the Lipschitz constant.
f(x):={x2sin(1x2)x≠00x=0..
Note that f is differentiable at x=0 since 1h|f(h)−f(0)|=|hsin(h−2)|≤|h|→0, and f′(x)=2xsin(1x2)−(2x)cos(1x2)χx≠0. now take the sequence xn:=1/√kπ to get f′(xn)=2√kπ(−1)kn→∞⟶∞.